Python: How can I run eval() in the local scope of a function -


i try use eval() in local scope of function. evaluate in global scope.

self contained examples:

1- code works:

var1 = 1 var2 = 2 var3 = 3     mydict = dict((name, eval(name)) name in ["var1",                                               "var2",                                               "var3"]) print(mydict["var1"])

2- throws nameerror lvar1

def test1():    lvar1 = 1    lvar2 = 2    lvar3 = 3    mydict = dict((name, eval(name)) name in ["lvar1",                                                  "lvar2",                                                  "lvar3"])    print(mydict["lvar1"])

3- same outcome 2.

def test2():     lvar1 = 1     lvar2 = 2     lvar3 = 3     mydict = dict((name, eval(name), locals()) name in ["lvar1",                                                             "lvar2",                                                             "lvar3"])     print(mydict["lvar1"])

save result of locals() (or vars()) call return function's local scope. otherwise, locals() inside generator expression return gen-expr's local scope.

def test3():     lvar1 = 1     lvar2 = 2     lvar3 = 3     scope = locals()     mydict = dict((name, eval(name, scope)) name in [                   "lvar1", "lvar2", "lvar3"])     print(mydict["lvar1"])

btw, dictionary creation not necessary:

mydict = locals()  # or vars()

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