Python word match -


i have list of urls , i'm trying filter them using specific key words word1 , word2, , list of stop words [stop1, stop2, stop3]. there way filter links without using many if conditions? got proper output when used if condition on each stop word, doesn't feasible option. following brute force method:

for link in url:    if word1 or word2 in link:       if stop1 not in link:           if stop2 not in link:               if stop3 not in link:                   links.append(link)

here's couple of options consider if in situation.

you can use list comprehension built in any , all functions filter out unwanted urls list:

urls = ['http://somewebsite.tld/word',         'http://somewebsite.tld/word1',         'http://somewebsite.tld/word1/stop3',         'http://somewebsite.tld/word2',         'http://somewebsite.tld/word2/stop2',         'http://somewebsite.tld/word3',         'http://somewebsite.tld/stop3/word1',         'http://somewebsite.tld/stop4/word1']  includes = ['word1', 'word2'] excludes = ['stop1', 'stop2', 'stop3']  filtered_url_list = [url url in urls if any(include in url include in includes) if all(exclude not in url exclude in excludes)]

or can make function takes 1 url argument, , returns true urls want keep , false ones don't, pass function along unfiltered list of urls built in filter function:

def urlfilter(url):     includes = ['word1', 'word2']     excludes = ['stop1', 'stop2', 'stop3']     include in includes:         if include in url:             exclude in excludes:                 if exclude in url:                     return false             else:                 return true  urls = ['http://somewebsite.tld/word',         'http://somewebsite.tld/word1',         'http://somewebsite.tld/word1/stop3',         'http://somewebsite.tld/word2',         'http://somewebsite.tld/word2/stop2',         'http://somewebsite.tld/word3',         'http://somewebsite.tld/stop3/word1',         'http://somewebsite.tld/stop4/word1']  filtered_url_list = filter(urlfilter, urls)

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