sql server - MS Sql order by numeric parts of string -


i need order query numeric parts.

i have lot of rows looks like: 

'abcd.1234.567' 'abcd.1234-2345' 'abcd.1234.1213.1'

so, want firs order first numeric part, second , therd. this:

'abcd.1234.567' 'abcd.1234.1213.1' 'abcd.1234-2345'

how can this?

upd: have tried use patindex function in order by, can figure out how numbers. 

order s.product, (case when patindex('% ,.,-%', s.product)=0 0                         else cast(substring(s.product, patindex('%[0-9]%', s.product), len(s.product)) int) end)

you use string split function 

declare @sampledata table (     name varchar(100) )  insert @sampledata values ('abcd.1234.567'), ('abcd.1234-2345'), ('abcd.1234.1213.1')

your query be

select * @sampledata sd outer apply (     select cast(t.value int) part1     [dbo].[splitstring](replace(sd.name,'-', '.'),'.') t     t.pos = 2 ) p1 outer apply (     select cast(t.value int) part2     [dbo].[splitstring](replace(sd.name,'-', '.'),'.') t     t.pos = 3 ) p2 outer apply (     select cast(t.value int) part3     [dbo].[splitstring](replace(sd.name,'-', '.'),'.') t     t.pos = 4 ) p3 order p1.[part1], p2.[part2], p3.part3

and string split function

create function [dbo].[splitstring] (@text varchar(max),@delimiter varchar(10)) returns table  return (      select pos = row_number() on (order (select null))         ,value = ltrim(rtrim(b.i.value('(./text())[1]', 'varchar(max)')))    (select x = cast('<x>'+ replace(@text,@delimiter,'</x><x>')+'</x>' xml).query('.'))     cross apply x.nodes('x') b(i) );

result:

name              part1  part2  part3 --------------------------------------- abcd.1234.567     1234   567    null abcd.1234.1213.1  1234   1213   1 abcd.1234-2345    1234   2345   null

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