operator precedence - Define variable in IF does not work in PHP - 


... elseif ($notes = json_decode($op->notes) && isset($notes->newset)){            // $notes = json_decode($op->notes);             $set = \app\set::find($notes->newset);             $settitle = $set->title;         } ...

the above elseif statement generates error trying property of non-object regarding line $set = \app\set::find($notes->newset)

passing through elseif block should mean $notes assigned in elseif , value of $notes->newset found.

i don't know why above snippet not works! works if uncomment // $notes = json_decode($op->notes);

the php version 7.0.18

as pointed out @zerkms, because of operator precedence, part of expression following

$notes =

is evaluated first, , in success case,

json_decode($op->notes) && isset($notes->newset)

evaluates true, resulting in $notes being assigned true, rather json_decode()d data want.

to fix issue, wrap assignment in parenthesis, , evaluated first, and, pointed out @jh1711, make sure verify decoded data object ( instance of stdclass), rather array:

} elseif (($notes = json_decode($op->notes)) instanceof \stdclass && isset($notes->newset)) {     $set = \app\set::find($notes->newset);     $settitle = $set->title; }

for reference, see:


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