c++11 - How to declare templated pointer to templated method? -


templated typedefs possible using. how can directly make templated method pointer?

example:

class myclass {    template<bool b> void fnc() { /*...*/ };    // can do:   template<bool b>   using tempptr = decltype(&myclass::fnc<b>);   //              ^^^^^^^^^^^^^^^^^^^^^^^^^^ };

how can write underlined part direcly, without decltype?

so far, have tried:

template<bool b> using tempptr = template<bool> void (myclass::*)();  template<bool b> using tempptr = void (myclass::*<b>)();  ...

(follow question: can use tempptras template template parameter?)

those work, giving different behaviour:

template<bool b> using ptr = void (myclass::*)();  using ptr2 = void (myclass::*)();  // alternatively //typedef void (myclass::*ptr2)();

to use:

myclass::ptr<true> ptr = &myclass::fnc<true>;  myclass::ptr2 ptr2 = &myclass::fnc<true>;

the bool parameter in ptr isn't same parameter in fnc. since template type isn't part of signature, mismatch bind fine, utilized other purposes:

myclass::ptr<false> ptr = &myclass::fnc<true>;

that's why nontemplated ptr2 works fine.


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