.net assembly - C#: Resolving multiple assemblies using the AssemblyResolve function -

i'm attempting make single exe app. end, have 2 dlls tagged embedded resouces in app. can use appdomain.currentdomain.assemblyresolve += new resolveeventhandler(myresolve) method return assembly when event fires.

the difficulty i'm running methods within application reference multiple assemblies. when use above event handler load , return assembly, application looks method in wrong assembly file, , "type load exception".

therefore, how can load assemblies application looks in proper places methods might use?

kind regards.

code sample:

dll resolution:

appdomain.currentdomain.assemblyresolve += new  resolveeventhandler(resolvedll)          static assembly resolvedll(object sender, resolveeventargs args)         {             using (var stream = assembly.getexecutingassembly().getmanifestresourcestream("myapplication.resources.mydll1.dll"))             {                 byte[] assemblydata = new byte[stream.length];                 stream.read(assemblydata, 0, assemblydata.length);                 return assembly.load(assemblydata); //obviously resolves first dll, how can resolve second?             }         }  void somemethod()  {   mydll1.class.callamethod()   mydll2.class.callanothermethod() //type load exception - assembly resolution told in mydll1.  } 

as per suggestion of l.b., tried simple if/then block using args.name. has done trick.

if (args.name == "mydll1, version=1.0.0.0, culture=neutral, publickeytoken=null")         {             using (var stream = assembly.getexecutingassembly().getmanifestresourcestream("myapplication.resources.mydll1.dll"))             {                 byte[] assemblydata = new byte[stream.length];                 stream.read(assemblydata, 0, assemblydata.length);                 return assembly.load(assemblydata);             }          }         else if (args.name == "mydll2, version=1.0.0.0, culture=neutral, publickeytoken=null")         {             using (var stream = assembly.getexecutingassembly().getmanifestresourcestream("myapplication.resources.mydll2.dll"))             {                 byte[] assemblydata = new byte[stream.length];                 stream.read(assemblydata, 0, assemblydata.length);                 return assembly.load(assemblydata);             }         }