Interpreter behaviour in Python -


i know python interpreter executes command line line without compiling entire program @ start. not understood why catching syntax errors on next subsequent lines without executing starting lines.

for example, in script, if write following statements:

print("i first") print("second") print(third")              # syntax error. missed 1 "

this gives below output:

file "script2.py", line 3      print(third")                 ^  syntaxerror: eol while scanning string literal

i expecting output below:

i first second file "script2.py", line 3      print(third")                 ^  syntaxerror: eol while scanning string literal

i keen learn why python interpreter exhibits behavior.

it depends on how run python interpreter. if give full source file, first parse whole file , convert bytecode before execution instruction. if feed line line, parse , execute code block block

so go one line @ time


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