Django URL in template with slug -

i have template (home.html) want list items in model, , when click on them, take user details page of item.

home.html:

{% item in menuitems %}      <div class="col-md-4">       <h2><a href="{% url 'show_menuitem' slug=instance.slug %}">{{ item }}</a></h2>       <p> </p>     </div>       {% endfor %} 

urls.py:

urlpatterns = [url(r'^menuitem/(?p<menuitem_slug>[-\w]+)/$', menu_views.show_menuitem, name = 'show_menuitem'), ] 

views.py:

def home(request): page_title = 'samplepagetitle' template_name="home.html" menuitems = menuitem.objects.all() context = { 'page_title':page_title, 'menuitems':menuitems, } return render(request, template_name, context) 

models.py:

class menuitem(models.model): name = models.charfield(max_length=250, blank=false, unique=true) slug = models.slugfield(max_length=250, unique=true,  def __str__(self):     return self.name  @models.permalink def get_absolute_url(self):     return ('show_menuitem', (), { 'menuitem_slug': self.slug }) 

i keep getting noreversematch error, says:

reverse 'show_menuitem' keyword arguments '{'slug': ''}' not found. 1 pattern(s) tried: ['menuitem/(?p[-\w]+)/$']

why giving me error? loop set wrong in template file?

in loop call each object item. in url tag refer instance, not exist. should use item there too.

{% url 'show_menuitem' menuitem_slug=item.slug %}