c - Why is the output reversed along with the first character missing? -


this question has answer here:

#include<stdio.h> int main() {     char *a;        char *temp ='55515';     = &temp;       printf("%s ", a); }

the expected output 55515 actual output 5155?

'55515' multi-character constant converted int. platform has 32-bit ints msb byte discarded, , resulting int (int)0x35353135. converted pointer char in implementation-defined manner. platform little-endian platform, , char conversion retains int value. value of pointer object laid out in memory 

temp:    | 0x35 | 0x31 | 0x35 | 0x35

or 

| 0x35 | 0x31 | 0x35 | 0x35

it cannot deducted whether or not you're using 64-bit or 32-bit platform. make another pointer char * points first byte of pointer object, i.e. byte 0x35, printf string %s.

depending on platform printf call has implementation-defined behaviour or possibly undefined behaviour - depends on whether pointers 32 or 64 bits wide - if 32, have undefined behaviour, if 64, you're depending on implementation-defined behaviour. in all, not strictly-conforming program rely on.


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