javascript - How to use the "or" command within JS regEx properly? -


i tried write more or less complex regex js. passes tests except 2 , don't know why. code

function telephonecheck(str) {   regex1 = /^[1]\s(\d{3}[-]){2}\d{4}|(\d{3}[-]){2}\d{4}$/;   regex2 = /^\d{10}$/;   regex3 = /^[1]\s(\d{3}\s){2}\d{4}|(\d{3}\s){2}\d{4}$/;   regex4 = /^[1]\s[(]{1}\d{3}[)]{1}\d{3}[-]{1}\d{4}|[(]{1}\d{3}[)]{1}\d{3}[-]{1}\d{4}$/;   regex5 = /^[1]\s[(]{1}\d{3}[)]{1}\s\d{3}[-]{1}\d{4}|[(]{1}\s\d{3}[)]{1}\d{3}[-]{1}\d{4}$/;   if (regex1.test(str) || regex2.test(str) || regex3.test(str) || regex4.test(str) || regex5.test(str)) {     return true;   }   else {     return false;   } }

and 2 test doesn't pass correctly (both should come false true instead): telephonecheck("2(757)622-7382") , telephonecheck("(555-555-5555"). question how use | (or) operator (i think make code way nicer) , how describe expression within regex match specific character (e.g. "1" @ beginning of number)? did [1]{1} or [1]$ didn't seem work. hints , suggestions!

how describe expression within regex match specific character (e.g. "1" @ beginning of number)

to match specific character, use character. x valid regex string match letter "x". match special character, escape first. regex . match character; regex \. match period.

note regex x equivalent [x] in match same things, former shorter , easier read. when given choice, use single character directly (escaped if necessary!) , forget [ ].

your regex's contain expressions [-], [(], , [1]. drop brackets. on second one, need escape (.

expressions [(]{1} equivalent \(. {1} means match previous item once. using item accomplishes same thing. 2 characters lot shorter 6 , make regex easier read.

how use | (or) operator properly

using | operator simple enough. match on left, or on right side. enclose in parenthesis restrict match. example, a|bc match "a" or "bc". (a|b)c match "ac" , "bc".


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