melt the lower half from systematic matrix in R -


given have 3 three systematic matrix.

> x<-matrix(1:9,3) > x[lower.tri(x)] = t(x)[lower.tri(x)] > x      [,1] [,2] [,3] [1,]    1    4    7 [2,]    4    5    8 [3,]    7    8    9

then apply library reshape2 make in long-format.

> library(reshape2) > x <- melt(x) > x   var1 var2 value 1    1    1     1 2    2    1     4 3    3    1     7 4    1    2     4 5    2    2     5 6    3    2     8 7    1    3     7 8    2    3     8 9    3    3     9

as upper diagonal , bottom diagonal identical, need half of result, below.

var1 var2 value    1    1     1    2    1     4    3    1     7    2    2     5    3    2     8    3    3     9

any elegant approach this?

you can change values bottom or upper half na, , melt ignoring missing values, assume there not missing values in matrix or don't need keep them in result if there are:

x[upper.tri(x)] = na reshape2::melt(x, na.rm=t)  #  var1 var2 value #1    1    1     1 #2    2    1     4 #3    3    1     7 #5    2    2     5 #6    3    2     8 #9    3    3     9

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