oracle - Sql to order results by sum -


db used - oracle

create table customer_exercise( customer_id number, exercise_id number, cnt number, exercise_date date)

table data

1000    10  3   17-dec-15 1001    20  6   19-dec-15 1000    20  2   20-dec-15 1003    20  9   20-dec-15 1000    20  6   22-dec-15 1000    30  10  23-dec-15 1001    10  25  10-dec-15

is possible results using sql such sum(cnt) exercise_id 20 appears first in resultset?

select customer_id , exercise_id, sum(cnt) customer_exercise  customer_id in (1000, 1001, 1003) , exercise_id in (20) group customer_id, exercise_id order sum(cnt)  1001    20  6 1000    20  8 1003    20  9   select customer_id , exercise_id, sum(cnt) customer_exercise  customer_id in (1000, 1001, 1003) , exercise_id not in (20) group customer_id, exercise_id order sum(cnt)  1000    10  3 1000    30  10 1001    10  25

what trying merge results of above 2 queries 1 sql. possible write single sql fetch resultset below?

1001    20  6 1000    20  8 1003    20  9 1000    10  3 1000    30  10 1001    10  25

i think be:

select customer_id , exercise_id, sum(cnt) customer_exercise  customer_id in (1000, 1001, 1003)  group customer_id, exercise_id order (case when exercise_id in (20) 1 else 2 end), sum(cnt)

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