javascript - How to pass many ajax results to different input values? -


my ajax return results 4 values.i want assign these values 4 input value.here ajax code:

$.ajax({  type:"post",  url:"modify_cbndtb.php",  data: {cabinetnum:id},  success:function (res)   {  }  });

modify_cbndtb.php code:

if(isset($_post['cabinetnum'])) {     $q=$_post["cabinetnum"];  $sql="select num1,num2,num3,num4  hpc sysid= '".$q."';";  $sel = $conn->query($sql); }

my html code:

<div id="content" class="content"> 1u:<input type="text" id="1u" value="">11u:<input type="text" id="11u" value=""><br /> 2u:<input type="text" id="2u" value="">12u:<input type="text" id="12u" value=""><br /> </div>

1u.value should num1. 2u.value should num2. 3u.value should num3. 4u.value should num4. don't know how realize. can me?

i think can try this

modify_cbndtb.php    if(isset($_post['cabinetnum']))   {         $q=$_post["cabinetnum"];      $sql="select num1,num2,num3,num4  hpc sysid= '".$q."';";      $sel = $conn->query($sql);      $arr = $sel->fetch(pdo::fetch_assoc);      $data = json_encode($arr);      echo $data;   }

and ajax

 client file   $.ajax({  type:"post",  url:"modify_cbndtb.php",  data: {cabinetnum:id},  success:function (data) {    $('#1u').val(data[0].num1);    $('#11u').val(data[0].num2);    $('#2u').val(data[0].num3);    $('#12u').val(data[0].num4);    }   });

i hope you


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