regex - SAS replacing a specific pattern without space back in the text -


for eg text this- "i have these codes c 6780, u 6780, c0555". output giving is- "i have these codes ([cu][0-9o][0-9a-z]{3}), ([cu][0-9o][0-9a-z]{3}), c0545". expecting "i have these codes c6780, u6780, c0555". tried code.

data replace_pat; set text; if _n_ =1 pattern = prxparse ("s/([cu]\s[0-9o][0-9a-z]{3})/([cu][0-9o][0-9a-z]{3})/"); retain pattern; call prxchange(pattern, -1, text);  run;

how change code achieve this?

you need enclose bits want keep in parens (not whole thing) create capture groups, refer capture groups using $1 $2.

data replace_pat;   set text;   if _n_ =1 pattern = prxparse ("s/([cu])\s([0-9o][0-9a-z]{3})/$1$2/");   retain pattern;   call prxchange(pattern, -1, text);  run;

you might want o option after final / avoid having silly if n = 1 bit.


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