c# - How to make the Show Properties window to stay always on top of a form already set to be always on top? -


i want call standard show properties window form. form on top , show properties window displayed below it. how make show properties window stay on top of form?

below code used show properties window.

    // show properties window     [dllimport("shell32.dll", charset = charset.auto)]     static extern bool shellexecuteex(ref shellexecuteinfo lpexecinfo);      [structlayout(layoutkind.sequential, charset = charset.auto)]     public struct shellexecuteinfo     {         public int cbsize;         public uint fmask;         public intptr hwnd;         [marshalas(unmanagedtype.lptstr)]         public string lpverb;         [marshalas(unmanagedtype.lptstr)]         public string lpfile;         [marshalas(unmanagedtype.lptstr)]         public string lpparameters;         [marshalas(unmanagedtype.lptstr)]         public string lpdirectory;         public int nshow;         public intptr hinstapp;         public intptr lpidlist;         [marshalas(unmanagedtype.lptstr)]         public string lpclass;         public intptr hkeyclass;         public uint dwhotkey;         public intptr hicon;         public intptr hprocess;     }      const int sw_show = 5;     const uint see_mask_invokeidlist = 12;      public static void showproperties(string filename)     {         shellexecuteinfo info = new shellexecuteinfo();         info.cbsize = marshal.sizeof(info);         info.lpverb = "properties";         info.lpfile = filename;         info.nshow = sw_show;         info.fmask = see_mask_invokeidlist;          shellexecuteex(ref info);     }

i thought disabling topmost property of form temporarily, have no idea how detect when show properties window has been closed activate topmost again.


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